Trigonometry Formulas class-10 Consider a right-angled triangle have angle ∠θ, then sin θ= Perpendicular / Hypotenuse = P/H Cos θ=Base / Hypotenuse = B/H Tan θ= Perpendicular / Base = P / B Cosec θ=1/sin θ Sec θ=1/cosθ Cot θ=1/tan θ Tan θ=Sin θ / Cos θ sin θ= Perpendicular / Hypotenuse = P/H Cos θ=Base / Hypotenuse = B/H Tan θ= Perpendicular / Base = P / B Cosec θ=1/sinθ Sec θ=1/cosθ Cot θ=1/tanθ Tan θ=Sin θ / Cos θ C o t T a n θ = S i n θ / C o s θ Trigonometry Table: Angle 0° 30° 45° 60° 90° Sinθ 0 1/2 1/√2 √3/2 1 Cosθ 1 √3/2 1/√2 ½ 0 Tanθ 0 1/√3 1 √3 Undefined Cotθ Undefined √3 1 1/√3 0 Secθ 1 2/√3 √2 ...
